RE: Weird K8 output

[YhLu]

Yes,

You are right,

You can change to 
//                upos = ht_c[i].upos;
                upos = ((reg & 0xf00)>>8) * 0x20 + 0x80;

last time, I remember because it will use up regs. But this time seems OK.

regards

Yinghai Lu
-----Original Message-----
From: Stefan Reinauer [mailto:[e-mail]] 
Sent: Tuesday, November 02, 2004 3:31 PM
To: YhLu
Subject: Re: Weird K8 output

* YhLu  [041102 21:27]:
> MB Model?
> HT routing table?

It was too loud (LOGLEVEL 9)

BUT:
> coherent_ht_finalize
> done
> PCI_DEV=(0,0x18,0) 0xb4=00030000
> bus=00 id =74501022
> bus=00 id =74601022
> PCI_DEV=(0,0x19,0) 0xd4=000a0400

<HANGS HERE>

static int ht_setup_chains(const struct ht_chain *ht_c, int ht_c_num)
takes:
                [...]
                { /* Link 1 of CPU0 */
                        .udev = PCI_DEV(0, 0x18, 0),
                        .upos = 0xa0,
                        .devreg = 0xe0,
                },
                { /* Link 2 of CPU1 */
                        .udev = PCI_DEV(0, 0x19, 0),
                        .upos = 0xc0,
                        .devreg = 0xe4, 
                },
                [...]

and resourcemap.c:
        PCI_ADDR(0, 0x18, 1, 0xE0), 0x0000FC88, 0x03000103,
        PCI_ADDR(0, 0x18, 1, 0xE4), 0x0000FC88, 0x0a040213,
        PCI_ADDR(0, 0x18, 1, 0xE8), 0x0000FC88, 0x0f0b0223,
        PCI_ADDR(0, 0x18, 1, 0xEC), 0x0000FC88, 0x14100133,

Question1:
I took the bus numbers above from the running machine. is this wrong? 
How would I calculate them correctly?

Question2:
isn't .upos duplicate?
ht_setup_chains reads the link to choose from .devreg. It could
determine .upos from there as well, no?

Stefan