On Tue, Jun 19, 2007 at 12:34:51PM -0400, Corey Osgood wrote:
No. The binary and is kinda weird, if you have, say, 11100011 and 01010101, the binary and will give an answer of which bits are the same between the two,
Not quite, that's XOR+NOT, exclusive or with inversion.
The truth table for AND is: a b y 0 0 0 0 1 0 1 0 0 1 1 1
The result is 1 only when both input bits are 1. The result is 0 otherwise.
so 01000001.
This is correct however.
11100011 & 01010101 -------- 01000001
(use a fixed width font)
//Peter