Map of the memory

[Xavier Pegenaute]

Hi,

i was trying to make a memory map in the eeprom but i have some
questions when i saw linuxbios_c.map and linuxbios.map ...

We "compile" linuxbios_c with c_start.o and linuxbios.a until generate
linuxbios_payload and linuxbios_c.map.

We "compile" crt0.S and we make the crt0.o.

After we "compile" crt0.o with linuxbios_payload generating linuxbios
binary and linuxbios.map

If we see inside the map files, i can see that there are labels at the
same position in the both map files for example:

linuxbios_c.map :
00004000 A _RAMBASE
00080000 A _ROMBASE

linuxbios.map:
00004000 A _RAMBASE
00080000 A _ROMBASE

How is it possible ? when in theory al linuxbios_c is in the payload of
linuxbios?

linuxbios.map:
000805a0 D _payload
00085e5d D _epayload

also i saw in some file (.ld) in the tree of freebios a picture of memory:

Memory map:

0x00000	(4*4096 bytes)	: stack
    0x04000	(4096 bytes)	: private data
    0x05000			: data space
    0x90000			: kernel stack
    0xf0000	(64 Kbyte)	: EPROM

Is it right ? i think that i'm confusing the memory in RAM and the
memory in EPROM. But i don't know how build a correct idea.

Thanks.
Xavi.