Am 02.03.2012 00:43 schrieb Stefan Tauner:
Previously we relied on a correctly set up state.
untested.
Signed-off-by: Stefan Tauner stefan.tauner@student.tuwien.ac.at
linux_spi.c | 23 +++++++++++++++++++++++ 1 files changed, 23 insertions(+), 0 deletions(-)
diff --git a/linux_spi.c b/linux_spi.c index d994389..d29c59a 100644 --- a/linux_spi.c +++ b/linux_spi.c @@ -57,6 +57,8 @@ int linux_spi_init(void) { char *p, *endp, *dev; uint32_t speed = 0;
- /* FIXME: make the following configurable by CLI options. */
- uint8_t mode = SPI_MODE_0, lsb = 0, bits = 0; /* mode 0, msb first, 8 bits */
Can you move that comment above the variable definitions? Where should we note that SPI_MODE_0 also implies CS# active low?
dev = extract_programmer_param("dev"); if (!dev || !strlen(dev)) { @@ -92,6 +94,27 @@ int linux_spi_init(void) msg_pdbg("Using %d kHz clock\n", speed); }
- if (ioctl(fd, SPI_IOC_WR_MODE, &mode) == -1) {
msg_perr("%s: failed to set SPI mode to %u: %s\n",
__func__, mode, strerror(errno));
close(fd);
return 1;
- }
- if (ioctl(fd, SPI_IOC_WR_LSB_FIRST, &lsb) == -1) {
msg_perr("%s: failed to set SPI justification to %u: %s\n",
__func__, lsb, strerror(errno));
This message would benefit from an explanation what SPI justification is. Suggestion: msg_perr("%s: failed to set SPI bit order to %s first: %s\n", __func_, lsb ? "LSB" : "MSB", strerror(errno));
close(fd);
return 1;
- }
- if (ioctl(fd, SPI_IOC_WR_BITS_PER_WORD, &bits) == -1) {
msg_perr("%s: failed to set the number of bits in an SPI word to %u: %s\n",
__func__, bits, strerror(errno));
bits is 0. The error message would suggest that we tried to set the number of bits to 0. Does 0 also mean 8 bits, or would we have to set 8 bits with bits=8?
close(fd);
return 1;
- }
- if (register_shutdown(linux_spi_shutdown, NULL)) return 1;
As an alternative, we could avoid the whole close(fd) dance by calling register_shutdown() first, and then letting it do the work for us automatically after we return 1.
Regards, Carl-Daniel